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Table 4 Percentage of RTECs that met the respective nutrient profiles by sample, target group and claim type

From: Health-related on-pack communication and nutritional value of ready-to-eat breakfast cereals evaluated against five nutrient profiling schemes

Parameter

Keyhole

IWG

EU

OFCOM

FSANZ

yes

yes

yes

yes

yes

% (n)

% (n)

% (n)

% (n)

% (n)

All German RTECs 2010 (n = 128)

4 (5)

16 (20)

28 (36)

14 (18)

23 (29)

Products by target (sample 2010)

Children RTECs (n = 58)

0 (0)

0 (0)

9 (5)

2 (1)

9 (5)

Non-Children RTECs (n = 70)

7 (5)

30 (21)

44 (31)

24 (17)

34 (24)

Chi-square test

a

0.000

0.000

0.000

0.001

Products by claim type (sample 2010)

Nutrition or Health Claim (n = 77)

5 (4)

22 (17)

35 (27)

16 (12)

26 (20)

No Nutrition or Health Claim (n = 51)

2 (1)

8 (4)

18 (9)

12 (6)

18 (9)

Chi-square test

a

0.049

0.044

0.612

0.291

Whole grain claim (n = 39)

10 (4)

41 (16)

46 (18)

21 (8)

36 (14)

No whole grain claim (n = 89)

1 (1)

6 (5)

20 (18)

11 (10)

17 (15)

Chi-square test

a

0.000

0.005

0.177

0.023

Clean labelling (n = 15)

13 (2)

27 (4)

40 (6)

40 (6)

47 (7)

No clean labelling (n = 113)

3 (3)

15 (17)

27 (30)

11 (12)

19 (22)

Chi-square Test

a

a

a

a

a

Healthy ingredients mentioned in product names (sample 2010)

Any healthy ingredient (n = 73)

6 (4)

23 (17)

33 (24)

15 (11)

25 (18)

No healthy ingredient (n = 55)

2 (1)

7 (4)

22 (12)

13 (7)

20 (11)

Chi-square Test

a

0.017

0.233

0.801

0.670

Products by production method (sample 2010)

Organically certified (n = 11)

9 (1)

18 (2)

46 (5)

46 (5)

55 (6)

Conventional (n = 117)

3 (4)

16 (19)

27 (31)

11 (13)

20 (23)

Chi-square Test

a

a

a

a

a

Products by country (sample 2012)

German RTECs 2012 (n = 73)

7 (5)

16 (12)

36 (26)

14 (10)

26 (19)

Norwegian RTECs 2012 (n = 38)

32 (12)

40 (15)

66 (25)

41 (15)b

60 (22)b

Chi-square Test

0.001

0.010

0.003

0.003

0.001

  1. a)Chi-square Test could not be applied, expected cell frequencies were below the adequate expected counts of 5 b)n = 37.